首页> 外文期刊>Journal of Combinatorial Theory, Series A >Dissecting the Stanley partition function
【24h】

Dissecting the Stanley partition function

机译:剖析Stanley分区功能

获取原文
获取原文并翻译 | 示例
       

摘要

Let p(n) denote the number of unrestricted partitions of n. For i = 0, 2, let pi (n) denote the number of partitions pi of n such that O(pi) - O(pi') = i (mod 4). Here O(pi) denotes the number of odd parts of the partition pi and pi' is the conjugate of pi. Stanley [Amer. Math. Monthly 109 (2002) 760; Adv. Appl. Math., to appear] derived an infinite product representation for the generating function of p(0)(n) - p(2)(n). Recently, Swisher [The Andrews-Stanley partition function and p(n), preprint, submitted for publication] employed the circle method to show that lim(n ->infinity) p(0)(n)/p(n) = 1/2 and that for sufficiently large n 2p(0)(n) > p(n) if n = 0, 1 (mod 4), 2p(0)(n) < p(n) otherwise. In this paper we study the even/odd dissection of the Stanley product, and show how to use it to prove (i) and (ii) with no restriction on n. Moreover, we establish the following new result: vertical bar p(0)(2n) - p(2)(2n)vertical bar > vertical bar p(0)(2n + 1) - p(2)(2n + 1)vertical bar, n > 0. Two proofs of this surprising inequality are given. The first one uses the Gollnitz-Gordon partition theorem. The second one is an immediate corollary of a new partition inequality, which we prove in a combinatorial manner. Our methods are elementary. We use only Jacobi's triple product identity and some naive upper bound estimates.
机译:令p(n)表示n的无限制分区数。对于i = 0,2,令pi(n)表示n的分区pi的数量,以使O(pi)-O(pi')= i(模4)。在此,O(pi)表示分区pi的奇数部分,并且pi'是pi的共轭数。史丹利[Amer。数学。每月109(2002)760;进阶应用数学,[出现]为p(0)(n)-p(2)(n)的生成函数导出了无限乘积表示。最近,Swisher [Andrews-Stanley分区函数和p(n),预印本,准备发布,已发表]使用圆法显示lim(n-> infinity)p(0)(n)/ p(n)= 1 / 2,如果n = 0,则对于足够大的n 2p(0)(n)> p(n),则1(mod 4),否则2p(0)(n)(n)。在本文中,我们研究了Stanley产品的偶数/奇数剖析,并展示了如何使用它来证明(i)和(ii),而对n没有任何限制。此外,我们建立以下新结果:竖线p(0)(2n)-p(2)(2n)竖线>竖线p(0)(2n + 1)-p(2)(2n + 1)垂直条,n>0。给出了这个令人惊讶的不等式的两个证明。第一个使用Gollnitz-Gordon分割定理。第二个是新的分区不等式的直接推论,我们以组合的方式证明了这一点。我们的方法是基本的。我们仅使用Jacobi的三元乘积标识和一些幼稚的上限估计。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号