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首页> 外文期刊>Journal of applied physiology >Comments on Point:Counterpoint: Muscle lactate and H production do/do not have a 1:1 association in skeletal muscle. Lactate and acidosis yet again?
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Comments on Point:Counterpoint: Muscle lactate and H production do/do not have a 1:1 association in skeletal muscle. Lactate and acidosis yet again?

机译:关于穴位对点的评论:乳酸和H的产生与骨骼肌之间没有1:1的关联。乳酸和酸中毒了吗?

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to the editor: This third debate (4) in the APS journals on the issue of lactate production and acidosis has at last narrowed the argument to a clear and manageable question: is there a 1:1 relationship between lactate and hydrogen ion production via glycolysis in muscle? The correct answer, as already noted by Dr. Sahlin both previously (see comments in Ref. 3) and today (see comments in Ref. 1), is yes, because with respect to its effect on hydrogen ion production in an aqueous solution, all that matters is the net reaction, and the only quantitatively significant net glyco-lytic reaction in muscle is just: glucose 2 lactic acid. At biological pH, lactic acid is essentially all dissociated to lactate and hydrogen ion. [Or, if one prefers the alternative Stewartian way to say the same thing (2), lactate is a strong ion.] Unfortunately, both the Point and Counterpoint obscure this simple truth by their detailed analyses of the individual steps along the glycolytic pathway. Of course, if done correctly, this approach will also yield the correct answer, as shown by Drs. Vinnakota and Kushmerick. However, were a completely different set of enzymatic steps to evolve or be devised by which glucose is converted to lactic acid, the net effect would still be exactly the same. Let us not confuse our students any further. We should bring this argument to a close.
机译:致编辑:关于乳酸产生和酸中毒问题的APS期刊的第三次辩论(4)最终将争论范围缩小到一个明确且易于处理的问题:通过糖酵解产生乳酸和氢离子之间是否存在1:1的关系在肌肉上?正如Sahlin博士先前(参见参考文献3中的注释)和今天(参见参考文献1中的注释)所指出的那样,正确答案是肯定的,因为就其对水溶液中氢离子产生的影响而言,重要的是净反应,肌肉中唯一在数量上有意义的净糖酵解反应就是:葡萄糖2乳酸。在生物pH下,乳酸基本上全部解离为乳酸和氢离子。 [或者,如果人们更喜欢用Stewartian的另一种方式来说同一件事(2),那么乳酸就是强离子。]不幸的是,Point和Counterpoint都通过对糖酵解途径中各个步骤的详细分析而掩盖了这个简单的事实。当然,如果操作正确,此方法也将产生正确的答案,如Drs所示。 Vinnakota和Kushmerick。但是,如果通过一套完全不同的酶促步骤来进化或设计出葡萄糖将其转化为乳酸的方法,其最终效果仍将完全相同。让我们不要进一步混淆我们的学生。我们应该结束这个论点。

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