首页> 外文会议>International Conference on Wireless and Telematics >The Analysis of Unbalanced Assignment Problems Using The Kotwal-Dhope Method To Develop A Massive Open Online Course
【24h】

The Analysis of Unbalanced Assignment Problems Using The Kotwal-Dhope Method To Develop A Massive Open Online Course

机译:使用Kotwal-Dhope方法分析不平衡分配问题以开发大规模在线公开课程

获取原文

摘要

This study discusses the optimal solution of the unbalanced assignment of minimization case in order to develop massive open online course in the Islamic Higher Education by using a new method that is the Kotwal-Dhope Method. The method was formed with the help of the Hungarian method and the Matrix One’s Assignment method was resolves the unbalanced assignment problem with a data size 8x4 which aims to minimize the total costs incurred by an Islamic Higher Education. The optimal solution with the Kotwal-Dhope Method begins by adding a dummy of one, carrying out the division operation of each column with the smallest element, after each row and column has a value of one, perform assignments in condition one so that each lecturer has their own job in develop massive open online course. Based on the results of this study it was found that, lecturer B was assigned to do stage 1 (Defining educational content), lecturer D was assigned to do stage 2 (Production and technical integration), lecturer E was assigned to do stage 3 (Communication), and lecturer H was assigned to do stage 4 (Course Animation and Overview). Then the assignments were: B → 1, D → 2, E → 3, H → 4. From the results of the assignment, the optimal solution for the minimum cost is 18 + 23 + 12 + 20 = 73 unit costs.
机译:本研究讨论了使用最小化案例的不平衡分配的最优解决方案,以便通过使用一种新的方法(即Kotwal-Dhope方法)在伊斯兰高等教育中开发大规模的开放在线课程。该方法是在匈牙利方法的帮助下形成的,而Matrix One的“分配”方法则解决了数据大小为8x4的不平衡分配问题,旨在最大程度地减少伊斯兰高等教育带来的总成本。使用Kotwal-Dhope方法的最佳解决方案是从添加一个虚拟对象1开始,对具有最小元素的每一列进行除法运算,在每一行和每一列的值都为1之后,在条件1下执行分配,以便每个讲师在开发大规模开放在线课程方面有自己的工作。根据研究结果,发现讲师B被指定为第一阶段(定义教育内容),讲师D被指定为第二阶段(生产和技术集成),讲师E被指定为第三阶段(定义教育内容)。交流),并指定讲师H进行第4阶段(课程动画和概述)。然后分配为:B→1,D→2,E→3,H→4。根据分配的结果,最小成本的最佳解决方案是18 + 23 + 12 + 20 = 73单位成本。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号