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The solution to a conjecture of Tits on the subgroup generated by the squares of the generators of an Artin group

机译:由Artin组生成器的平方生成的子群上的Tit猜想的解

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Let A be an Artin group with standard generating set {σ_s:s ∈ S}. Tits conjectured that the only relations in A amongst the squares of the generators are consequences of the obvious ones, namely that σ_s~2 and σ_t~2 commute whenever σ_s and σ_t commute, for s,t ∈ S. In this paper we prove Tits' conjecture for all Artin groups. In fact, given a number m_s ≥ 2 for each s ∈ S, we show that the elements {T_s = σ_s~(m_s):s ∈ S} generate a subgroup that has a finite presentation in which the only defining relations are that T_s and T_t commute if σ_s and σ_t commute.
机译:设A为标准生成集{σ_s:s∈S}的Artin组。 Tits猜想,生成器的平方之间的A唯一关系是明显的平方的结果,即σ_s和σ_t上下通勤时,对于s,t∈S,σ_s〜2和σ_t〜2上下通。所有Artin团体的猜想。实际上,给定每个s∈S的数m_s≥2,我们证明元素{T_s =σ_s〜(m_s):s∈S}生成一个子集,该子集具有有限的表示形式,其中唯一的定义关系是T如果σ_s和σ_t通勤,则T_t通勤。

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