...
首页> 外文期刊>Journal of Combinatorial Theory, Series A >A combinatorial duality between the weak and strong Bruhat orders
【24h】

A combinatorial duality between the weak and strong Bruhat orders

机译:弱者和强大的布鲁哈特订单之间的组合二元性

获取原文
获取原文并翻译 | 示例
           

摘要

In recent work, the authors used an order lowering operator del, introduced by Stanley, to prove the strong Sperner property for the weak Bruhat order on the symmetric group. Hamaker, Pechenik, Speyer, and Weigandt interpreted del as a differential operator on Schubert polynomials and used this to prove a new identity for Schubert polynomials and a determinant conjecture of Stanley. In this paper we study a raising operator Delta for the strong Bruhat order on the symmetric group, which is in many ways dual to del. We prove a Schubert identity dual to that of Hamaker et al. and derive formulas for counting weighted paths in the Hasse diagrams of the strong order which agree with path counting formulas for the weak order, providing a strong order analog of Macdonald's reduced word identity. We also show that powers of del and Delta have the same Smith normal forms, which we describe explicitly, answering a question of Stanley. (C) 2019 Elsevier Inc. All rights reserved.
机译:在最近的工作中,作者使用了由斯坦利推出的降低运营商Del,以证明对称组的弱Bruhat订单的强斜尖属性。 Hamaker,Pechenik,Speyer和Weigandt将Del解释为Schubert多项式的差分运营商,并用它来证明Schubert多项式的新身份和斯坦利的决定因素猜想。 在本文中,我们研究了对称组的强烈Bruhat命令的筹集运营商三角洲,这是在许多方面与Del的方式。 我们证明了哈布尔特的身份双重地到了Hamaker等人。 并导出配方,用于计算强烈秩序的哈斯特图中的加权路径,这与弱订单的路径计数公式一致,提供了麦克唐纳减少单词标识的强烈秩序。 我们还表明,Del和Delta的权力具有相同的史密斯正常形式,我们明确描述,回答了斯坦利的问题。 (c)2019 Elsevier Inc.保留所有权利。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号