...
【24h】

Identification of the strongest bonds in chemistry

机译:鉴定化学上最强的键

获取原文
获取原文并翻译 | 示例
           

摘要

Increasing the effective electronegativity of two atoms forming a triple bond can increase the strength of the latter. The strongest bonds found in chemistry involve protonated species of hydrogen cyanide, carbon monoxide, and dinitrogen. CCSD(T)/CBS (complete basis set) and G4 calculations reveal that bond dissociation energies are misleading strength descriptors. The strength of the bond is assessed via the local stretching force constants, which suggest relative bond strength orders (RBSO) between 2.9 and 3.4 for heavy atom bonding (relative to the CO bond strength in methanol (RBSO = 1) and formaldehyde (RBSO = 2)) in [HCNH]~+(~1Σ~+), [HCO] ~+(~1Σ~+), [HNN]~+(~1Σ~+), and [HNNH]~(2+)(~1Σ _g ~+). The increase in strength is caused by protonation, which increases the electronegativity of the heavy atom and thereby decreases the energy of the bonding AB orbitals (A, B: C, N, O). A similar effect can be achieved by ionization of a nonbonding or antibonding electron in CO or NO. The strongest bond with a RBSO value of 3.38 is found for [HNNH]~(2+) using scaled CCSD(T)/CBS frequencies determined for CCSD(T)/CBS geometries. Less strong is the NN bond in [FNNH]~(2+) and [FNNF]~(2+).
机译:增加形成三键的两个原子的有效电负性可提高后者的强度。化学中发现的最强键涉及氰化氢,一氧化碳和二氮的质子化物质。 CCSD(T)/ CBS(完整基集)和G4计算表明,键离解能是误导性的强度描述符。通过局部拉伸力常数评估键的强度,这表明重原子键的相对键强度阶数(RBSO)在2.9和3.4之间(相对于甲醇中的CO键强度(RBSO = 1)和甲醛(RBSO = 2))中的[HCNH]〜+(〜1Σ〜+),[HCO]〜+(〜1Σ〜+),[HNN]〜+(〜1Σ〜+)和[HNNH]〜(2 +)( 〜1Σ_g〜+)。强度的增加是由质子化引起的,质子化增加了重原子的电负性,从而降低了键合AB轨道(A,B:C,N,O)的能量。通过使CO或NO中的非键电子或反键电子电离,可以达到类似的效果。使用针对CCSD(T)/ CBS几何结构确定的CCSD(T)/ CBS比例频率,发现[HNNH]〜(2+)的RBSO值最强。 [FNNH]〜(2+)和[FNNF]〜(2+)中的NN键强度较弱。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号