微波辐射下甲基丙烯酸缩水甘油酯的合成

摘要

Using cetyltrimethylammonium bromide as the catalyst and phenothiazine as the inhibitor,glycidyl methacrylate (GMA) is prepared by Sodium methacrylate (MAA-Na) and epichlorohydrin (ECH) under microwave irradiation.The optimum reaction conditions are obtained by single factor experiment and response surface optimization experiment:n (MAA-Na) ∶ n (ECH) =1 ∶ 5,reaction temp.is 90 ℃,reaction time is 20 min,microwave power is 500 W,the catalyst dosage is 20％ (about the quality of MAA-Na).Under these conditions the yield of product can be reached 80.60％.FT-IR and 1H NMR characterization results show that the resulting product is the target product.%在催化剂十六烷基三甲基溴化铵和阻聚剂吩噻嗪的存在下,使甲基丙烯酸钠(MAA-Na)和环氧氯丙烷(ECH)在微波辐射下合成甲基丙烯酸缩水甘油酯(GMA),产物经红外和核磁进行了确证.采用单因素实验初步确定较佳合成条件,并用响应面法优化实验方案,得到最佳反应条件为:n(MAA-Na)∶n(ECH)=1∶5,反应温度90℃,反应时间20 min,微波功率为500 W,催化剂用量20％(与MAA-Na的量比),在此条件下产率可达80.60％.