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A Game of Cops and Robbers on Graphs with Periodic Edge-Connectivity

机译:具有周期性边缘连接的图表上的警察和劫匪的游戏

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This paper considers a game in which a single cop and a single robber take turns moving along the edges of a given graph G. If there exists a strategy for the cop which enables it to be positioned at the same vertex as the robber eventually, then G is called cop-win, and robber-win otherwise. In contrast to previous work, we study this classical combinatorial game on edge-periodic graphs. These are graphs with an infinite lifetime comprised of discrete time steps such that each edge e is assigned a bit pattern of length l_e, with a 1 in the i-th position of the pattern indicating the presence of edge e in the i-th step of each consecutive block of l_e steps. Utilising the known framework of reachability games, we obtain an O(LCM(L) ? n~3) time algorithm to decide if a given n-vertex edge-periodic graph G~т is cop-win or robber-win as well as compute a strategy for the winning player (here, L is the set of all edge pattern lengths l_e, and LCM(L) denotes the least common multiple of the set L). For the special case of edge-periodic cycles, we prove an upper bound of 2 l ? LCM(L) on the minimum length required of any edge-periodic cycle to ensure that it is robber-win, where l = 1 if LCM(L) ≥ 2 ? max L, and l = 2 otherwise. Furthermore, we provide constructions of edge-periodic cycles that are cop-win and have length 1.5 ? LCM(L) in the l = 1 case and length 3 ? LCM(L) in the l = 2 case.
机译:本文考虑了一个游戏,其中单个警察和单个强盗轮流沿着给定图G的边缘移动。如果存在扑克的策略,这使得它能够以强盗最终将其定位在同一顶点上,则g称为COP-WIN,否则强盗。与以前的工作相比,我们在边缘周期性图上研究了这种古典组合游戏。这些是具有由离散时间步骤组成的无限寿命的图,使得每个边缘E被分配一个长度L_E的比特模式,其中图案的第i个位置是第i步骤中的边缘E的存在。每个连续的L_E步骤块。利用已知的可达性游戏框架,我们获得O(lcm(l)?n〜3)时间算法来确定给定的n-顶点边缘周期图g〜т是cop-win或强盗赢计算获胜播放器的策略(这里,L是所有边缘图案长度L_E的集合,LCM(L)表示集合L的最小常见倍数)。对于特殊的边缘周期周期,我们证明了2 L的上限? LCM(L)在任何边缘周期周期所需的最小长度上,以确保它是抢劫者,其中L = 1如果LCM(L)≥2?最大l,否则l = 2。此外,我们提供了由COP-WIN的边缘周期循环的结构,并且具有长度为1.5? LCM(L)在L = 1案和长度3中? LCM(L)在L = 2例。

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