摘要:
Let (a,b,c) be a primitive Pythagorean triple such that a2+b2 =c2,gcd (a,b) =1 and2|b.In this paper,using some elementary number theory methods,the positive integer solutions (x,y,z,n) of the equation (an)x + bny =(cn)z are discussed.We prove that if (a,b,c) =(143,24,145),then the equation has only the positive integer solutions (x,y,z,n) =(2,2,2,m),where m is an arbitrary positive integer.The above result verifies Je(s)anowicz conjecture for this case.%设(a,b,c)是一组满足a2+ b2=c2,gcd(a,b)=1,2|b的本原商高数,运用初等数论方法讨论方程(an)x+(bn)y=(cn)z正整数解(x,y,z,n),证明了:当(a,b,c)=(143,24,145)时,方程仅有正整数解(x,y,z,n)=(2,2,2,m),其中m是任意正整数,上述结果说明此时Je(s)manowicz猜想成立.