首页> 外国专利> Abrasion Resistant Steel which includes (Mass percentage) 0.05 to 0.35 C, 0.05 - 0.1 - 1.0, 2.0 Mn, 0.1 - 1.2 percent, 0.1 or less of the element of a 0.1 - 1.0 Cu, 0.1 - 2.0 ni,0.1 - 1.0 Cr, 0.05 to 1.0 Mo, 0.05 to 1.0 per cent W, 0

Abrasion Resistant Steel which includes (Mass percentage) 0.05 to 0.35 C, 0.05 - 0.1 - 1.0, 2.0 Mn, 0.1 - 1.2 percent, 0.1 or less of the element of a 0.1 - 1.0 Cu, 0.1 - 2.0 ni,0.1 - 1.0 Cr, 0.05 to 1.0 Mo, 0.05 to 1.0 per cent W, 0

机译:耐磨钢,以0.1-1.0%Cu,0.1-2.0%的含量(质量百分比)C,0.05-0.35%C,0.05-0.1-1.0%,2.0%Mn,0.1-1.2%,0.1%以下ni,0.1-1.0%Cr,0.05至1.0%Mo,0.05至1.0%W,0

摘要

An abrasion resistant steel excellent in bending formability and suitable for members, e.g., power shovels, which come into contact with earth and sand, and a production method thereof are provided. Specifically, the steel contains, on a percent by mass basis, 0.05% to 0.35% of C, 0.05% to 1.0% of Si, 0.1% to 2.0% of Mn, 0.1% to 1.2% of Ti, 0.1% or less of Al, at least one element of 0.1% to 1.0% of Cu, 0.1% to 2.0% of Ni, 0.1% to 1.0% of Cr, 0.05% to 1.0% of Mo, 0.05% to 1.0% of W, and 0.0003% to 0.0030% of B, if necessary at least one element of 0.005% to 1.0% of Nb and 0.005% to 1.0% of V, and the remainder including Fe and incidental impurities, where DI* represented by the following formula is less than 60. DI * = 33.85 × 0.1 × C * 0.5 × 0.7 × Si + 1 × 3.33 × Mn + 1 × 0.35 × Cu + 1 × 0.36 × Ni + 1 × 2.16 × Cr + 1 × 3 × Mo * + 1 × 1.5 × W * + 1 where C* = C - 1/4 × (Ti - 48/14N), Mo* = Mo × (1 - 0.5 × (Ti - 48/14N)), and W* = W × (1 - 0.5 × (Ti - 48/14N)).
机译:本发明提供了一种弯曲成形性优异,适用于与土,沙接触的部件例如电铲的耐磨钢及其制造方法。具体地,以质量百分比计,钢包含0.05%至0.35%的C,0.05%至1.0%的Si,0.1%至2.0%的Mn,0.1%至1.2%的Ti,0.1%以下的C。 Al,0.1%至1.0%的Cu,0.1%至2.0%的Ni,0.1%至1.0%的Cr,0.05%至1.0%的Mo,0.05%至1.0%的W和0.0003%中的至少一种元素至B的0.0030%,如果需要,至少一种元素为Nb的0.005%至1.0%,V的0.005%至1.0%,其余包括Fe和附带杂质,其中下式表示的DI *小于60 DI * = 33.85×0.1×C * 0.5×0.7×Si + 1×3.33×Mn + 1×0.35×Cu + 1×0.36×Ni + 1×2.16×Cr + 1×3×Mo * + 1×1.5 ×W * + 1其中C * = C-1/4×(Ti-48 / 14N),Mo * = Mo×(1-0.5×(Ti-48 / 14N)),W * = W×(1-0.5×(Ti -48 / 14N))。

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