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Monotonicity of order preserving operator functions

机译:保单操作员功能的单调性

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We discuss monotonicity of order preserving operator functions and related order preserving operator inequalities. Let A >= B >= 0 with A > 0, t is an element of [0, 1] and p >= 1. Let F(lambda, mu) = A(-lambda/2){A(lambda/2) (A(-1/2) B-p A(-1/2))(mu) A(lambda/2)}(1-t+lambda/(p-1)mu+lambda) A(-lambda/2). We show that: (i) F(r, w) >= F(r, 1) >= F(r, s) >= F(r, s') for any s' >= s >= 1, r >= t and 1-t/p-t <= w <= 1, (ii) F(q, s) >= F(t, s) >= F(r, s) >= F(r', s) for any r' >= r >= t, s >= 1 and t-1 <= q <= t. These imply the following recent inequality due to Kamei A(t) #(1-t/p-t) B-p >= A(1/2) F(r, s)A(1/2) for r >= t and s >= 1. (c) 2007 Elseiver Inc. All rights reserved.
机译:我们讨论了保序算子功能的单调性和相关的保序算子不等式。设A> = B> = 0且A> 0,则t是[0,1]的元素,且p> =1。设F(lambda,mu)= A(lambda / 2){A(lambda / 2) )(A(-1/2)Bp A(-1/2))(mu)A(lambda / 2)}(1-t + lambda /(p-1)mu + lambda)A(-lambda / 2 )。我们证明:(i)对于任何s'> = s> = 1,r(i,F(r,w)> = F(r,1)> = F(r,s)> = F(r,s') > = t和1-t / pt <= w <= 1,(ii)F(q,s)> = F(t,s)> = F(r,s)> = F(r',s)对于任何r'> = r> = t,s> = 1且t-1 <= q <= t。这意味着由于r> = t和s>的Kamei A(t)#(1-t / pt)Bp> = A(1/2)F(r,s)A(1/2)而导致的以下最近不等式。 =1。(c)2007 Elseiver Inc.保留所有权利。

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