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首页> 外文期刊>Electrochimica Acta >Studies on electrochemical hydrodebromination mechanism of 2,5-dibromobenzoic acid on Ag electrode by in situ FTIR spectroscopy
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Studies on electrochemical hydrodebromination mechanism of 2,5-dibromobenzoic acid on Ag electrode by in situ FTIR spectroscopy

机译:原位FTIR光谱研究Ag电极上2,5-二溴苯甲酸的电化学加氢脱溴机理

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摘要

Cyclic voltammetry and in situ FTIR were employed to study the electrochemical hydrodebromination (EHB) mechanism of 2,5-dibromobenzoic acid (2,5-DBBA) in NaOH solution. Compared with titanium and graphite electrodes, silver electrode exhibited a high electrocatalytic activity for the hydrodebromination reaction of 2,5-DBBA. On the basis of in situ FTIR data, EHB reaction of 2,5-DBBA on Ag cathode might be represented as a sequence of electron additions and bromine expulsions. Firstly, from potential at approximately -1100 mV, 2,5-DBBA received an electron to form 2,5-DBBA radical anion, which lost a bromine ion in the 2-position to form 3-bromobenzoic acid (3-BBA) free radical. Then the free radical received a proton to give 3-BBA. Finally, 3-BBA further took off another bromine ion to produce benzoic acid free radical and the end product benzoic acid was obtained by receiving another electron and a proton with the potential shifting to more negative values.
机译:采用循环伏安法和原位FTIR研究了NaOH溶液中2,5-二溴苯甲酸(2,5-DBBA)的电化学加氢脱溴(EHB)机理。与钛和石墨电极相比,银电极对2,5-DBBA的加氢脱溴反应具有较高的电催化活性。根据原位FTIR数据,2,5-DBBA在银阴极上的EHB反应可能表示为电子添加和溴排出的顺序。首先,从大约-1100 mV的电势开始,2,5-DBBA接收电子以形成2,5-DBBA自由基阴离子,该阴离子在2位失去一个溴离子,从而形成游离的3-溴苯甲酸(3-BBA)激进。然后自由基接受质子以产生3-BBA。最后,3-BBA进一步脱去另一个溴离子以产生苯甲酸自由基,并通过接收另一个电子和质子将电位转移到更多的负值来获得最终产物苯甲酸。

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