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COLORING HYPERGRAPHS DEFINED BY STABBED PSEUDO-DISKS AND ABAB-FREE HYPERGRAPHS

机译:由刺伤伪磁盘和无骨头图像定义的着色超图

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摘要

What is the minimum number of colors that always suffice to color every planar set of points such that any disk that contains enough points contains two points of different colors? It is known that the answer to this question is either three or four. We show that three colors always suffice if the condition must be satisfied only by disks that contain a fixed point. Our result also holds, and is even tight, when instead of disks we consider their topological generalization, namely, pseudo-disks, with a nonempty intersection. Our solution uses the equivalence that a hypergraph can be realized by stabbed pseudo-disks if and only if it is ABAB-free. These hypergraphs are defined in a purely abstract, combinatorial way, and our proof that they are 3-chromatic is also combinatorial.
机译:始终足以颜色的最小颜色数量是多少,每个平面点都有,使得包含足够点的任何磁盘包含两点不同颜色的磁盘?众所周知,这个问题的答案是三四。我们展示三种颜色始终足够就足够的,如果条件只能由包含固定点的磁盘满足。我们的结果也持有,甚至紧张,当我们考虑他们的拓扑泛化,即伪磁盘,带有非空交叉路口的话。我们的解决方案使用了当且仅当它是无亚本尾的伪磁盘可以通过刺伤伪磁盘来实现的等价。这些超图是以纯粹的摘要,组合方式定义的,我们证明它们是3-彩色也是组合的。

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