...
首页> 外文期刊>Food Science and Biotechnology >Prediction of consumer acceptability of potato chips with various moisture contents using survival analysis
【24h】

Prediction of consumer acceptability of potato chips with various moisture contents using survival analysis

机译:使用生存分析预测各种水分含量的薯片的消费者可接受性

获取原文
获取原文并翻译 | 示例
           

摘要

Consumer acceptability of potato chips with different moisture contents (MC) was evaluated using survival analysis. Nine different humidity conditions (30–70%) at 25°C were used. MC values of samples ranged from 2.2–9.2% after treatment. Panelists (50) were asked to rate chip acceptability. The chip MC was predicted using non-linear models. Panelist-generated data were categorized as left, interval, and right censored. A total of 18 panelists were left censored and 30 were interval censored. Weibull and lognormal distributions were used to fit the censored data. The mean MC of chips rejected by 50% of consumers were 3.54% (95% confidence interval, 3.14–3.99%) and 3.60% (CI 3.23–4.01%) for the Weibull and lognormal distribution, respectively. These values corresponded to 5.7 and 5.6 overall consumer liking values (Weibull and lognormal distributions, respectively). MC of 3.5–3.6% was necessary to attain consumer acceptability values of 5.6 and product acceptance by 50% of consumers.
机译:使用生存分析评估了不同水分含量(MC)的薯片的消费者可接受性。在25°C下使用了9种不同的湿度条件(30–70%)。处理后样品的MC值范围为2.2–9.2%。专门小组成员(50)被要求对芯片的可接受性进行评分。使用非线性模型预测芯片MC。专门小组成员生成的数据分为左,间隔和右检查。共有18名小组成员被审查,30名被间隔审查。使用Weibull和对数正态分布来拟合审查数据。对于威布尔分布和对数正态分布,被50%的消费者拒绝的芯片的平均MC分别为3.54%(95%置信区间,3.14-3.99%)和3.60%(CI 3.23-4.01%)。这些值对应于5.7和5.6总体消费者喜好值(分别为Weibull和对数正态分布)。 MC必须达到3.5-3.6%,才能达到5.6的消费者接受度和50%的消费者接受产品。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号