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Rindler space derivation of dark energy

机译:暗能量的林德勒空间推导

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We present a miraculously short derivation of the missing dark energy density of the universe which is in absolute agreement with the most recent accurate cosmological measurements and observations. The derivation is based upon a Rindler space setting, the associated wedge horizon and Unruh temperature. That way the topological ordinary energy is found to be half of the topological Unruh fluctuation mass m(O) = φ3 multiplied with the square of the topological speed of light c2 = φ2 where = φ = 2 /( 5 + 1). This is exactly equal to the area of the spear-like hyperbolic triangular part of the Rindler wedge. The corresponding physical ordinary energy density is thus E(O) = (1/2) ( φ3)( φ2) mc2 = (φ5/2)( mc2), where φ5 is Hardy’s probability of quantum entanglement. The topological dark energy density on the other hand is equal half of the topological Kaluza-Klein five dimensional mass m(D) = 5 multiplied with c2 = φ2. This in turn is exactly equal to the circular segment part of the wedge which together with the hyperbolic triangular entangled area forms the complete Lorentzian invariant triangular area of the wedge. Consequently the physical dark energy density which is uncorrelated is given by E(D) = (1/2) (5)( φ2)( mc2) = (5 φ2 /2)( mc2) in full agreement with observation. Adding E(O) and E(D) one finds E(Einstein) = mc2.
机译:我们提出了一个奇迹般的短暂的宇宙缺失的暗能量密度的推导,它与最新的精确宇宙学测量和观测绝对一致。该推导基于Rindler空间设置,关联的楔形水平和Unruh温度。这样,发现拓扑普通能量是拓扑Unruh波动质量m(O)=φ3乘以光拓扑速度c2 =φ2的平方的一半,其中=φ= 2 /(5 +1)。这恰好等于Rindler楔形的矛状双曲线三角形部分的面积。因此,相应的物理普通能量密度为E(O)=(1/2)(φ3)(φ2)mc2 =(φ5/ 2)(mc2),其中φ5是哈迪量子纠缠的概率。另一方面,拓扑暗能量密度等于拓扑Kaluza-Klein五维质量m(D)= 5乘以c2 =φ2的一半。这又恰好等于楔形的圆形部分,它与双曲线三角形纠缠区域一起构成楔形的完整洛伦兹不变三角形区域。因此,与观测完全一致,不相关的物理暗能量密度由E(D)=(1/2)(5)(φ2)(mc2)=(5φ2/ 2)(mc2)给出。将E(O)和E(D)相加得出E(爱因斯坦)= mc2。

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