Let $M= left[ egin{array}{cc} A& B C& O end{array} ight]$ be a complex square matrix where A is square. When BCB^{Omega} =0, rank(BC) = rank(B) and the group inverse of $left[ egin{array}{cc} B^{Omega} A B^{Omega} & 0 CB^{Omega} & 0 ight]$ exists, the group inverse of M exists if and only if rank(BC + A)B^{Omega}AB^{Omega})^{pi}B^{Omega}A)= rank(B). In this case, a representation of $M^#$ in terms of the group inverse and Moore-Penrose inverse of its subblocks is given. Let A be a real matrix. The sign pattern of A is a (0,+,?)-matrix obtained from A by replacing each entry by its sign. The qualitative class of A is the set of the matrices with the same sign pattern as A, denoted by Q(A). The matrix A is called S^2GI, if the group inverse of each matrix ar{A} in Q(A) exists and its sign pattern is independent of e A. By using the group inverse representation, a necessary and sufficient condition for a real block matrix to be an S^2GI-matrix is given.
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机译:令$ M = left [ begin {array} {cc} A&B C&O end {array} right] $是一个复杂的正方形矩阵,其中A是正方形。当BCB ^ { Omega} = 0时,rank(BC)= rank(B)且$ left [ begin {array} {cc} B ^ { Omega} AB ^ { Omega}&0的组逆 CB ^ { Omega}&0 right] $存在,并且仅当rank(BC + A)B ^ { Omega} AB ^ { Omega})^ { pi}时,M的组逆才存在B ^ { Omega} A)=等级(B)。在这种情况下,给出了$ M ^#$的子块逆和Moore-Penrose逆的表示。令A为实矩阵。 A的符号模式是通过用符号替换每个条目而从A获得的(0,+ ,?)矩阵。 A的定性类是具有与A相同符号模式的矩阵的集合,用Q(A)表示。如果存在Q(A)中每个矩阵 bar {A}的组逆,并且其符号模式与e A无关,则矩阵A称为S ^ 2GI。通过使用组逆表示,可以满足以下条件:给出了一个真正的块矩阵为S ^ 2GI矩阵。
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