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首页> 外文期刊>Communications in Nonlinear Science and Numerical Simulation >Vertex circulation and regularity of compressible Stokes flows: Numerical simulations
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Vertex circulation and regularity of compressible Stokes flows: Numerical simulations

机译:顶点循环和可压缩斯托克斯流的规律性:数值模拟

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We investigate the vertex circulation in a cone-like form of compressible Stokes flows and show existence and regularity by constructing the solutions in the infinite sector attached to a fixed vertex, say the origin (0,0). Let omega be the opening angle of the sector. We construct the velocity vector u and the density function rho of the following formsu(x, y) = r(lambda)(phi(theta)e + psi(theta)e'), theta is an element of (0, omega),rho (x, y) = r(lambda-1)sigma (theta)where phi, psi and sigma are the solutions for a nonlinear boundary value problem with any positive number lambda not equal n pi / omega for integer n; r = root x(2) + y(2), theta are the polar coordinates at the origin, e = (cos theta, sin theta) and e' ( - sin theta, cos theta).The vertex can be a junction point that inflow and outflow meet and may result in a vertex circulation that means a cone-like rotation at vertex. The vertex circulation by compressible Stokes flows may blow up due to the singular behavior of suddenly change at corner. The angular velocity component is found to be positive while for lambda is an element of (0, 1) the velocity vector itself vanishes at the vertex and the pressure blows up there. We also demonstrate this phenomena by numerical simulations. (C) 2018 Elsevier B.V. All rights reserved.
机译:我们以可压缩的斯托克斯流的锥状形式研究顶点循环,并通过在固定于顶点(即原点(0,0))的无限扇形中构造解来显示存在性和规则性。令ω为扇形的张开角。我们构造速度向量u和以下形式的密度函数rho u(x,y)= r(λ)(phiθe+psiθe'),θ是(0,Ω)的元素,rho(x,y)= r(lambda-1)sigma(θ)其中phi,psi和sigma是非线性边值问题的解决方案,对于整数n,任何正数lambda不等于n pi / omega; r =根x(2)+ y(2),theta是原点的极坐标,e =(cos theta,sin theta)和e'(-sin theta,cos theta)。顶点可以是一个结点流入和流出相遇并可能导致顶点循环,这意味着顶点处呈圆锥状旋转。由于拐角处突然变化的奇异行为,可压缩斯托克斯流所产生的顶点循环可能会爆炸。发现角速度分量为正,而对于λ为(0,1)的元素,速度矢量本身在顶点处消失,并且压力在此处爆炸。我们还通过数值模拟证明了这种现象。 (C)2018 Elsevier B.V.保留所有权利。

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