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Aneuploidy as a mechanism for stress-induced liver adaptation

机译:非整倍体作为应激诱导肝脏适应的机制

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摘要

Over half of the mature hepatocytes in mice and humans are aneuploid and yet retain full ability to undergo mitosis. This observation has raised the question of whether this unusual somatic genetic variation evolved as an adaptive mechanism in response to hepatic injury. According to this model, hepatotoxic insults select for hepatocytes with specific numerical chromosome abnormalities, rendering them differentially resistant to injury. To test this hypothesis, we utilized a strain of mice heterozygous for a mutation in the homogentisic acid dioxygenase (Hgd) gene located on chromosome 16. Loss of the remaining Hgd allele protects from fumarylacetoacetate hydrolase (Fah) deficiency, a genetic liver disease model. When adult mice heterozygous for Hgd and lacking Fah were exposed to chronic liver damage, injury-resistant nodules consisting of Hgd-null hepatocytes rapidly emerged. To determine whether aneuploidy played a role in this phenomenon, array comparative genomic hybridization (aCGH) and metaphase karyotyping were performed. Strikingly, loss of chromosome 16 was dramatically enriched in all mice that became completely resistant to tyrosinemia-induced hepatic injury. The frequency of chromosome 16–specific aneuploidy was approximately 50%. This result indicates that selection of a specific aneuploid karyotype can result in the adaptation of hepatocytes to chronic liver injury. The extent to which aneuploidy promotes hepatic adaptation in humans remains under investigation.
机译:小鼠和人类中一半以上的成熟肝细胞为非整倍体,但仍保留了完整的有丝分裂能力。这项观察提出了一个问题,即这种异常的体细胞遗传变异是否作为适应机制对肝损伤作出反应。根据该模型,肝毒性损伤选择具有特定数字染色体异常的肝细胞,从而使其对损伤具有不同的抵抗力。为了检验该假设,我们利用杂合子小鼠品系对位​​于16号染色体上的高纯酸双加氧酶(Hgd)基因进行了突变。剩余的Hgd等位基因的丢失可防止遗传性肝病模型富马酰乙酰乙酸水解酶(Fah)缺乏。当成年小鼠的Hgd杂合子和缺乏Fah暴露于慢性肝损伤时,由Hgd无效的肝细胞组成的抗损伤结节迅速出现。为了确定非整倍性是否在这种现象中起作用,进行了阵列比较基因组杂交(aCGH)和中期核型分析。令人惊讶的是,在所有对酪氨酸血症引起的肝损伤完全耐受的小鼠中,第16号染色体的丢失显着丰富。 16号染色体特异性非整倍性的频率约为50%。该结果表明,选择特定的非整倍性核型可以导致肝细胞适应慢性肝损伤。非整倍体在人类中促进肝适应的程度仍在研究中。

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