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α-Crystallin. Fractionation of subunits and sequence studies on an isolated polypeptide

机译:α-晶体蛋白。亚基的分离和分离多肽的序列研究

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摘要

α-Crystallin was carboxymethylated with radioactive iodoacetic acid in the presence of 7.6m-urea and then separated into six major fractions by chromatography on DEAE-cellulose in 7m-urea. Based on the amino acid compositions, specific radioactivities and sodium dodecyl sulphate–gel electrophoresis of the fractions, it was concluded that α-crystallin contains at least four different subunits: DU1A and DU1B, containing no cysteine; a third component represented by DU2B and DU3 containing one cysteine one cysteine residue per subunit; and DU4, which probably contains two residues of cysteine per subunit. Subunit DU1A was shown to be of sufficient purity for sequence studies. Cyanogen bromide cleavage yielded two peptides, CB-1 and CB-2, in approximately equal amounts as expected. The sum of the molecular weights and amino acid compositions of the peptides were both in excellent agreement with the results obtained for subunit DU1A. The amino acid sequence of the first sixteen residues of peptide CB-1 is: Ser-Leu-Thr-Lys-Asp-Phe-Asp-Glu-Val-Asn-Ile-Asp-Val-Ser-His-Phe-. The sequence of the first seventeen residues of peptide CB-2 is: Asp-Ile-Ala-Ile-Ser-His-Pro-Trp-Ile-Arg-Pro-Ser-Phe-Phe-Glu-Phe-His-. The N-terminal sequence of subunit DU1A was shown to be N-acetylmethionine followed by peptide CB-2.
机译:在7.6m-尿素的存在下,用放射性碘乙酸将α-结晶蛋白羧甲基化,然后在7m-尿素中通过DEAE-纤维素色谱分离为六个主要部分。根据各组分的氨基酸组成,比放射性和十二烷基硫酸钠-凝胶电泳,得出结论,α-晶状体蛋白至少包含四个不同的亚基:DU1A和DU1B,不含半胱氨酸。由DU2B和DU3代表的第三组分,每个亚基含有一个半胱氨酸,一个半胱氨酸残基。 DU4,每个亚基可能包含两个半胱氨酸残基。已显示DU1A亚基具有足够的纯度用于序列研究。溴化氰的裂解产生了两个肽,CB-1和CB-2,与预期的量大致相等。肽的分子量和氨基酸组成的总和与从亚基DU1A获得的结果非常吻合。肽CB-1的前十六个残基的氨基酸序列是:Ser-Leu-Thr-Lys-Asp-Phe-Asp-Glu-Val-Asn-Ile-Asp-Val-Ser-His-Phe-。肽CB-2的前十七个残基的序列为:Asp-Ile-Ala-Ile-Ser-His-Pro-Trp-Ile-Arg-Pro-Ser-Phe-Phe-Glu-Phe-His-。 DU1A亚基的N端序列显示为N-乙酰甲硫氨酸,其后是肽CB-2。

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