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Calculation of interaction of AlCl, AlCl2 and AlCl3 on Al4C3 (001) Al4CO4 (001) and Al2CO (001) planes

机译:计算AlCl,AlCl2和AlCl3在Al4C3(001)Al4CO4(001)和Al2CO(001)平面上的相互作用

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To make sure the intermediate products of the carbothermic reduction of Al2O3 process, such as Al4CO4, Al2CO and Al4C3, and the interaction of AlCl, AlCl2, AlCl3 with Al4CO4, Al2CO and Al4C3, respectively, thermodynamic analyses were used to study the chloride reaction production of them under the vacuum situation. The stable structures and electronic properties of AlCl, AlCl2 and AlCl3 adsorbed on Al4CO4, Al2CO and Al4C3 were calculated by first-principles calculations by the CASTEP module in the Materials Studio program. The results show that the AlCl3 and AlCl2 molecules have decomposed on the plane of Al4C3 (001), while there are no obvious decomposition of AlCl3 and AlCl2 on Al4CO4 (001) and Al2CO (001) planes. The adsorption of AlCl on the Al4CO4 (001) and Al2CO (001) planes is stronger than that on the Al4C3(001) plane. The interaction strength of AlCl3, as well as AlCl2, with Al4CO4, Al2CO and Al4C3 is in the sequence of Al4CO4Al2CO>Al4C3.
机译:为了确定Al2O3的碳热还原中间产物,如Al4CO4,Al2CO和Al4C3,以及AlCl,AlCl2,AlCl3与Al4CO4,Al2CO和Al4C3的相互作用,分别使用热力学分析研究了氯化物的产生他们处于真空状态。通过Materials Studio程序中的CASTEP模块的第一性原理计算,得出了AlCl,AlCl2和AlCl3吸附在Al4CO4,Al2CO和Al4C3上的稳定结构和电子性能。结果表明,AlCl3和AlCl2分子在Al4C3(001)平面上分解,而AlCl3和AlCl2在Al4CO4(001)和Al2CO(001)平面上没有明显分解。 AlCl在Al4CO4(001)和Al2CO(001)平面上的吸附要强于Al4C3(001)平面。 AlCl3以及AlCl2与Al4CO4,Al2CO和Al4C3的相互作用强度按Al4CO4 Al2CO> Al4C3的顺序排列。

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