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Online Knapsack Problem with Removal Cost

机译:带搬运费用的在线背包问题

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In this paper, we study the online knapsack problem with removal cost. The input is a sequence of items u_1,u_2, ... ,u_n, each of which has a size and a value, where the value of each item is assumed to be equal to the size. Given the ith item u_i, we either put u_i into the knapsack or reject it with no cost. When u_i is put into the knapsack, some items in the knapsack are removed with removal cost if the sum of the size of u_i and the total size in the current knapsack exceeds the capacity of the knapsack. Here the removal cost means a cancellation charge or disposal fee. Our goal is to maximize the profit, i.e., the sum of the values of items in the last knapsack minus the total removal cost occurred. In this paper, we consider two kinds of removal cost: unit and proportional cost. For both models, we provide their competitive ratios. Namely, we construct optimal online algorithms and prove that they are best possible.
机译:在本文中,我们研究了带有搬运成本的在线背包问题。输入是项目u_1,u_2,...,u_n的序列,每个项目都有一个大小和一个值,其中每个项目的值都假定等于该大小。给定第i个项u_i,我们要么将u_i放进背包,要么不收任何费用将其拒绝。将u_i放入背包时,如果u_i的大小与当前背包的总大小之和超过背包的容量,则会删除背包中的某些物品并产生去除成本。在此,清除费用是指取消费用或处置费用。我们的目标是使利润最大化,即最后一个背包中物品的价值之和减去发生的总搬运费用。在本文中,我们考虑两种清除成本:单位成本和比例成本。对于这两种模型,我们都提供其竞争比率。即,我们构造了最佳的在线算法,并证明它们是最佳的。

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