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On Locating Disjoint Segments with Maximum Sum of Densities

机译:关于以最大密度求和的不相交线段的定位

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Given a sequence A of n real numbers and two positive integers l and k, where k ≤ n/l, the problem is to locate k disjoint segments of A, each has length at least l, such that their sum of densities is maximized. The best previously known algorithm, due to Bergkvist and Damaschke, runs in O(nl + k~2l~2) time. In this paper, we give an O(n + k~2l log l)-time algorithm.
机译:给定n个实数和两个正整数l和k的序列A,其中k≤n / l,问题是要找到A的k个不相交的段,每个段的长度至少为1,以使它们的密度之和最大化。由于Bergkvist和Damaschke,以前最好的算法是O(nl + k〜2l〜2)时间。在本文中,我们给出了O(n + k〜2l log l)-时间算法。

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