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Bounded Unpopularity Matchings

机译:有界不受欢迎匹配

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We investigate the following problem: given a set of jobs and a set of people with preferences over the jobs, what is the optimal way of matching people to jobs? Here we consider the notion of popularity. A matching M is popular if there is no matching M' such that more people prefer M' to M than the other way around. Determining whether a given instance admits a popular matching and, if so, finding one, was studied in [2]. If there is no popular matching, a reasonable substitute is a matching whose unpopularity is bounded. We consider two measures of unpopularity - unpopularity factor denoted by u(M) and unpopularity margin denoted by g(M). McCutchen recently showed that computing a matching M with the minimum value of u(M) or g(M) is NP-hard, and that if G does not admit a popular matching, then we have u(M) ≥ 2 for all matchings M in G. Here we show that a matching M that achieves u(M) = 2 can be computed in O(m (n~(1/2))) time (where m is the number of edges in G and n is the number of nodes) provided a certain graph H admits a matching that matches all people. We also describe a sequence of graphs: H = H_2,H_3,... ,H_k such that if H_k admits a matching that matches all people, then we can compute in O(km(n~(1/2))) time a matching M such that u(M) ≤ k- 1 and g(M) ≤ n(1-(2/k)). Simulation results suggest that our algorithm finds a matching with low unpopularity.
机译:我们研究以下问题:给定一组工作和一组对工作有偏爱的人,将人们与工作匹配的最佳方法是什么?在这里,我们考虑普及的概念。如果没有匹配的M',那么匹配的M很流行,这样比起其他方式,更多的人更喜欢M'。在[2]中研究了确定一个给定的实例是否允许一个流行的匹配,如果是,则找到一个匹配。如果没有受欢迎的匹配项,则合理的替代项是其受欢迎程度有限的匹配项。我们考虑不受欢迎度的两种度量-由u(M)表示的不受欢迎因素和由g(M)表示的不受欢迎裕度。 McCutchen最近表明,计算具有u(M)或g(M)最小值的匹配M是NP-hard,并且如果G不接受流行匹配,则所有匹配的u(M)≥2 G表示M。在这里,我们证明可以在O(m(n〜(1/2)))的时间内计算出达到u(M)= 2的匹配M(其中m是G中的边数,而n是(节点的数量),前提是某个图表H允许匹配所有人的匹配项。我们还描述了一系列图:H = H_2,H_3,...,H_k,使得如果H_k允许匹配所有人的匹配项,则可以计算O(km(n〜(1/2)))时间匹配M,使得u(M)≤k-1和g(M)≤n(1-(2 / k))。仿真结果表明,我们的算法找到了匹配度较低的匹配项。

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